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block: use bdev_alignment_offset in part_alignment_offset_show

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Replace the open coded offset calculation with the proper helper.
This is an ABI change in that the -1 for a misaligned partition is
properly propagated, which can be considered a bug fix and matches
what is done on the whole device.

Signed-off-by: Christoph Hellwig <hch@lst.de>
Reviewed-by: Martin K. Petersen <martin.petersen@oracle.com>
Reviewed-by: Chaitanya Kulkarni <kch@nvidia.com>
Link: https://lore.kernel.org/r/20220415045258.199825-17-hch@lst.de
Signed-off-by: Jens Axboe <axboe@kernel.dk>
This commit is contained in:
Christoph Hellwig 2022-04-15 06:52:47 +02:00 • committed by Jens Axboe
parent 2aba0d19f4
commit 64dcc7c271
1 changed files with 1 additions and 5 deletions
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6
block/partitions/core.c
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@ -200,11 +200,7 @@ static ssize_t part_ro_show(struct device *dev,
static ssize_t part_alignment_offset_show(struct device *dev, static ssize_t part_alignment_offset_show(struct device *dev,
struct device_attribute *attr, char *buf) struct device_attribute *attr, char *buf)
{ {
struct block_device *bdev = dev_to_bdev(dev); return sprintf(buf, "%u\n", bdev_alignment_offset(dev_to_bdev(dev)));
return sprintf(buf, "%u\n",
queue_limit_alignment_offset(&bdev_get_queue(bdev)->limits,
bdev->bd_start_sect));
} }
static ssize_t part_discard_alignment_show(struct device *dev, static ssize_t part_discard_alignment_show(struct device *dev,